0.20x^2-16=0

Solution for 0.20x^2-16=0 equation:

0.20x^2-16=0

a = 0.20; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·0.20·(-16)
Δ = 12.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{12.8}}{2*0.20}=\frac{0-\sqrt{12.8}}{0.4}
=-\frac{\sqrt{}}{0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{12.8}}{2*0.20}=\frac{0+\sqrt{12.8}}{0.4}
=\frac{\sqrt{}}{0.4}
$